Mathematics · 2014
JEE Main · 12 April 2014, Shift 1 · Q80
For the two circles x^2+y^2=16 and x^2+y^2-2 y=0, there is/are:
For the two circles $\displaystyle x^2+y^2=16$ and $\displaystyle x^2+y^2-2 y=0$, there is/are :
Official answer
(4)
no common tangent
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JEE Main 2014 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.