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Mathematics · 2015

JEE Main · 11 April 2015, Shift 1 · Q71

The equation of a normal to the curve, sin y=x sin ((π)/3+y) at x=0, is:

The equation of a normal to the curve, $\displaystyle \sin y=x \sin \left(\frac{\pi}{3}+y\right)$ at $\displaystyle x=0$, is :
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JEE Main 2015 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.