Mathematics · 2022
JEE Main · 26 July 2022, Shift 2 · Q12
The equation of a common tangent to the parabolas y=x^2 and y=-(x-2)^2 is
The equation of a common tangent to the parabolas $\displaystyle y=x^2$ and $\displaystyle y=-(x-2)^2$ is
Official answer
(2)
$\displaystyle y=4(x-1)$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.