Mathematics · 2022
JEE Main · 26 July 2022, Shift 2 · Q5
Let P and Q be any points on the curves (x-1)^2+(y+1)^2=1 and y=x^2, respectively. The distance between P and Q is minimum for some value of the…
Let P and Q be any points on the curves $\displaystyle (x-1)^2+(y+1)^2=1$ and $\displaystyle y=x^2$, respectively. The distance between $\displaystyle P$ and $\displaystyle Q$ is minimum for some value of the abscissa of P in the interval
Official answer
(3)
$\displaystyle \left(\frac{1}{4}, \frac{1}{2}\right)$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.