Mathematics · 2015
JEE Main · 10 April 2015, Shift 1 · Q71
The distance, from the origin, of the normal to the curve, x=2 cos t+2 t sin t, y=2 sin t-2 t cos t at t=(π)/4, is:
The distance, from the origin, of the normal to the curve, $\displaystyle x=2 \cos t+2 t \sin t$, $\displaystyle y=2 \sin t-2 t \cos t$ at $\displaystyle t=\frac{\pi}{4}$, is :
Official answer
(3)
$\displaystyle 2$
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JEE Main 2015 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.