Mathematics · 2022
JEE Main · 25 June 2022, Shift 2 · Q7
The coefficient of x^101 in the expression (5+x)^500+x(5+x)^499+x^2(5+x)^498+… …+x^500, x>0, is
The coefficient of $\displaystyle x^{101}$ in the expression $\displaystyle (5+x)^{500}+x(5+x)^{499}+x^2(5+x)^{498}+\ldots \ldots+x^{500}, x>0$, is
Official answer
(1)
$\displaystyle { }^{501} \mathrm{C}_{101}(5)^{399}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.