Mathematics · 2022
JEE Main · 29 July 2022, Shift 1 · Q16
The area of the region {(x, y):|x-1| ≤ y ≤ √(5-x^2)} is equal to:
The area of the region $\displaystyle \left\{(x, y):|x-1| \leq y \leq \sqrt{5-x^2}\right\}$ is equal to :
Official answer
(4)
$\displaystyle \frac{5 \pi}{4}-\frac{1}{2}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.