Mathematics · 2013
JEE Main · 22 April 2013, Shift 1 · Q66
The area of the region (in sq. units), in the first quadrant, bounded by the parabola y=9 x^2 and the lines x=0, y=1 and y=4, is:
The area of the region (in sq. units), in the first quadrant, bounded by the parabola $\displaystyle y=9 x^2$ and the lines $\displaystyle x=0, y=1$ and $\displaystyle y=4$, is :
Official answer
(4)
$\displaystyle 14$/$\displaystyle 9$
More from Area Under the Curve
- The area (in square units) of the region enclosed by the ellipse x^2+3 y^2=18 in the first quadrant below the line y=x is2024
- Let f:(1, ∞) → R be a function defined as f(x)=(x-1)/(x+1). Let f^i+1(x)=f(f^i(x)), i=1,2, …, 25, where f^1(x)=f(x). If g(x)+f^26(x)=0, x ∈(1, ∞),…2026
- The area of the region given by A={(x, y): x^2 ≤ y ≤ min {x+2,4-3 x}} is:2022
- The area (in square units) of the region bounded by the parabola y^2=4(x-2) and the line y=2 x-8, is:2024
- The area of the region A={(x, y): 4 x^2+y^2 ≤ 8. and.y^2 ≤ 4 x} is:2026
- If the area of the region {(x, y): a/x^2 ≤ y ≤ 1/x, 1 ≤ x ≤ 2,0<a<1} is ( log_e 2)-1/7 then the value of 7 a-3 is equal to:2024
- If the area enclosed between the curves y=k x^2 and x=k y^2,(k>0), is 1 square unit. Then k is:2019
- Given: f(x)= {x, 0 ≤ x<1/2; 1/2, x=1/2; 1-x, 1/2<x ≤ 1} and g(x)=(x-1/2)^2, x ∈ R. Then the area (in sq. units) of the region bounded by the curves,…2020
JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.