Mathematics · 2022
JEE Main · 26 June 2022, Shift 2 · Q7
The area of the region bounded by y^2=8 x and y^2=16(3-x) is equal to:
The area of the region bounded by $\displaystyle y^2=8 x$ and $\displaystyle y^2=16(3-x)$ is equal to:
Official answer
(3)
$\displaystyle 16$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.