Mathematics · 2020
JEE Main · 3 September 2020, Shift 1 · Q61
The area (in sq. units) of the region {(x, y): 0 ≤ y ≤ x^2+1,0 ≤ y ≤ x+1.,.1/2 ≤ x ≤ 2} is:
The area (in sq. units) of the region $\displaystyle \left\{(x, y): 0 \leq y \leq x^2+1,0 \leq y \leq x+1\right.$, $\displaystyle \left.\frac{1}{2} \leq x \leq 2\right\}$ is :
Official answer
(4)
$\displaystyle \frac{79}{24}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.