Mathematics · 2022
JEE Main · 29 June 2022, Shift 1 · Q6
The area enclosed by y^2=8 x and y=√ 2 x that lies outside the triangle formed by y=√ 2 x, x=1, y=2 √ 2, is equal to:
The area enclosed by $\displaystyle y^2=8 x$ and $\displaystyle y=\sqrt{2} x$ that lies outside the triangle formed by $\displaystyle y=\sqrt{2} x, x=1, y=2 \sqrt{2}$, is equal to :
Official answer
(3)
$\displaystyle \frac{13 \sqrt{2}}{6}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.