Mathematics · 2021
JEE Main · 18 March 2021, Shift 2 · Q70
The area bounded by the curve 4 y^2=x^2(4-x)(x-2) is equal to:
The area bounded by the curve $\displaystyle 4 y^2=x^2(4-x)(x-2)$ is equal to :
Official answer
(4)
$\displaystyle \frac{3 \pi}{2}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.