(2^3-1^3)/(1 × 7)+(4^3-3^3+2^3-1^3)/(2 × 11)+(6^3-5^3+4^3-3^3+2^3-1^3)/(3 × 15)+⋯+ (30^3-29^3+28^3-27^3+…+2^3-1^3)/(15 × 63) is equal to \ \ \ \.

$\displaystyle \begin{aligned} & \frac{2^3-1^3}{1 \times 7}+\frac{4^3-3^3+2^3-1^3}{2 \times 11}+\frac{6^3-5^3+4^3-3^3+2^3-1^3}{3 \times 15}+\cdots+ \\ & \frac{30^3-29^3+28^3-27^3+\ldots+2^3-1^3}{15 \times 63} \text { is equal to }\end{aligned}$ \_\_\_\_.