Let Σ_n =0^∞ (n^3((2 n )!)+(2 n -1)( n!))/(( n!)((2 n )!))= ae +b/e+ c, where a, b, c ∈ Z and e=Σ_n =0^∞ 1/(n!) Then a^2- b + c is equal to ____.

Let $\displaystyle \sum_{\mathrm{n}=0}^{\infty} \frac{\mathrm{n}^3((2 \mathrm{n})!)+(2 \mathrm{n}-1)(\mathrm{n}!)}{(\mathrm{n}!)((2 \mathrm{n})!)}=\mathrm{ae}+\frac{\mathrm{b}}{\mathrm{e}}+\mathrm{c}$, where a, b, c $\displaystyle \in \mathbb{Z}$ and $\displaystyle e=\sum_{\mathrm{n}=0}^{\infty} \frac{1}{\mathrm{n}!}$ Then $\displaystyle \mathrm{a}^2-\mathrm{b}+\mathrm{c}$ is equal to $\displaystyle \_\_\_\_$.