Mathematics · 2024
JEE Main · 30 January 2024, Shift 1 · Q24
Let α=1^2+4^2+8^2+13^2+19^2+26^2+… upto 10 terms and β=Σ_n=1^10 n^4. If 4 α-β=55 k+40, then k is equal to ____.
Let $\displaystyle \alpha=1^2+4^2+8^2+13^2+19^2+26^2+\ldots$ upto $\displaystyle 10$ terms and $\displaystyle \beta=\sum_{n=1}^{10} n^4$. If $\displaystyle 4 \alpha-\beta=55 k+40$, then k is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
353
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.