Mathematics · 2019
JEE Main · 9 April 2019, Shift 1 · Q89
Let S ={θ ∈[-2 π, 2 π]: 2 cos^2 θ+3 sin θ=0}. Then the sum of the elements of S is:
Let $\displaystyle \mathrm{S}=\left\{\theta \in[-2 \pi, 2 \pi]: 2 \cos ^2 \theta+3 \sin \theta=0\right\}$.
Then the sum of the elements of S is :
Official answer
(3)
$\displaystyle 2 \pi$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.