Mathematics · 2022
JEE Main · 26 July 2022, Shift 1 · Q9
Let f(x)= {x^3-x^2+10 x-7, x ≤ 1; -2 x+ log_2(b^2-4), x>1.}. Then the set of all values of b, for which f(x) has maximum value at x=1, is:
Let $\displaystyle f(x)=\left\{\begin{array}{cc}x^3-x^2+10 x-7, & x \leq 1 \\ -2 x+\log _2\left(b^2-4\right), & x>1 .\end{array}\right.$.
Then the set of all values of b , for which $\displaystyle f(x)$ has maximum value at $\displaystyle x=1$, is :
Official answer
(3)
$\displaystyle [-6,-2) \cup(2,6]$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.