Mathematics · 2020
JEE Main · 4 September 2020, Shift 1 · Q62
Let f(x)=∫ (√ x)/((1+x)^2) d x(x ≥ 0). Then f(3)-f(1) is equal to:
Let $\displaystyle f(x)=\int \frac{\sqrt{x}}{(1+x)^2} \mathrm{~d} x(x \geqslant 0)$. Then $\displaystyle f(3)-f(1)$ is equal to :
Official answer
(2)
$\displaystyle \frac{\pi}{12}+\frac{1}{2}-\frac{\sqrt{3}}{4}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.