Mathematics · 2022
JEE Main · 27 June 2022, Shift 2 · Q5
Let S=2+6/7+12/7^2+20/7^3+30/7^4+…. Then 4 S is equal to
Let $\displaystyle S=2+\frac{6}{7}+\frac{12}{7^2}+\frac{20}{7^3}+\frac{30}{7^4}+\ldots$. Then $\displaystyle 4 S$ is equal to
Official answer
(3)
$\displaystyle \left(\frac{7}{3}\right)^3$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.