Mathematics · 2019
JEE Main · 11 January 2019, Shift 2 · Q67
Let (x+10)^50+(x-10)^50 =a_0+a_1 x+a_2 x^2+…+a_50 x^50, for all x ∈ R; then (a_2)/(a_0) is equal to:
Let $\displaystyle (x+10)^{50}+(x-10)^{50}$
$$=a_0+a_1 x+a_2 x^2+\ldots+a_{50} x^{50} \text {, for all }
$$
$\displaystyle x \in \mathbf{R}$; then $\displaystyle \frac{\mathrm{a}_2}{\mathrm{a}_0}$ is equal to :
Official answer
(3)
$\displaystyle 12.25$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.