Mathematics · 2022
JEE Main · 28 July 2022, Shift 2 · Q69
Let I_n(x)=∫_0^x 1/((t^2+5)^n) d t, n=1,2,3, …. Then:
Let $\displaystyle I_n(x)=\int_0^x \frac{1}{\left(t^2+5\right)^n} d t, n=1,2,3, \ldots$. Then :
Official answer
(1)
$\displaystyle 50 I_6-9 I_5=x I_5^{\prime}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.