Let the tangent to the parabola y^2=12 x at the point (3, α) be perpendicular to the line 2 x +2 y =3. Then the square of distance of the point…

Let the tangent to the parabola $\displaystyle \mathrm{y}^2=12 \mathrm{x}$ at the point $\displaystyle (3, \alpha)$ be perpendicular to the line $\displaystyle 2 \mathrm{x}+2 \mathrm{y}=3$. Then the square of distance of the point $\displaystyle (6,-4)$ from the normal to the hyperbola $\displaystyle \alpha^2 x^2-9 y^2=9 \alpha^2$ at its point $\displaystyle (\alpha-1, \alpha+2)$ is equal to $\displaystyle \_\_\_\_$.