Mathematics · 2022
JEE Main · 24 June 2022, Shift 2 · Q3
Let the system of linear equations x+y+α z=2; 3 x+y+z=4; x+2 z=1 have a unique solution (x^*, y^*, z^*). If (α, x^*),(y^*, α) and (x^*,-y^*) are…
Let the system of linear equations
$$\begin{aligned}
& x+y+\alpha z=2 \\
& 3 x+y+z=4 \\
& x+2 z=1
\end{aligned}
$$
have a unique solution $\displaystyle \left(x^*, y^*, z^*\right)$. If $\displaystyle \left(\alpha, x^*\right),\left(y^*, \alpha\right)$ and $\displaystyle \left(x^*,-y^*\right)$ are collinear points, then the sum of absolute values of all possible values of $\displaystyle \alpha$ is
Official answer
(3)
$\displaystyle 2$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.