Mathematics · 2022
JEE Main · 24 June 2022, Shift 2 · Q22
Let S={ (-1, a; 0, b); a, b ∈{1,2,3, … 100}} and let T_n={A ∈ S: A^n(n+1)=I}. Then the number of elements in _n=1^100 T_n is \ \ \ \.
Let $\displaystyle S=\left\{\left(\begin{array}{cc}-1 & a \\ 0 & b\end{array}\right) ; a, b \in\{1,2,3, \ldots 100\}\right\}$ and let $\displaystyle T_n=\left\{A \in S: A^{n(n+1)}=I\right\}$. Then the number of elements in $\displaystyle \bigcap_{n=1}^{100} T_n$ is \_\_\_\_.
Official answer
100
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.