Let the plane P: 4 x-y+z=10 be rotated by an angle (π)/2 about its line of intersection with the plane x+y-z=4. If α is the distance of the point…

Let the plane P: $\displaystyle 4 x-y+z=10$ be rotated by an angle $\displaystyle \frac{\pi}{2}$ about its line of intersection with the plane $\displaystyle x+y-z=4$. If $\displaystyle \alpha$ is the distance of the point $\displaystyle (2,3,-4)$ from the new position of the plane P , then $\displaystyle 35 \alpha$ is equal to