Let the plane x+3 y-2 z+6=0 meet the co-ordinate axes at the points A, B, C. If the orthocenter of the triangle ABC is (α, β, 6/7), then 98(α+β)^2 is…

Let the plane $\displaystyle x+3 y-2 z+6=0$ meet the co-ordinate axes at the points $\displaystyle \mathrm{A}, \mathrm{B}, \mathrm{C}$. If the orthocenter of the triangle ABC is $\displaystyle \left(\alpha, \beta, \frac{6}{7}\right)$, then $\displaystyle 98(\alpha+\beta)^2$ is equal to $\displaystyle \_\_\_\_$.