Mathematics · 2024
JEE Main · 5 April 2024, Shift 2 · Q24
Let the maximum and minimum values of (√(8 x-x^2-12)-4)^2+(x-7)^2, x ∈ R be M and m, respectively. Then M^2- m^2 is equal to ____.
Let the maximum and minimum values of $\displaystyle \left(\sqrt{8 x-x^2-12}-4\right)^2+(x-7)^2, x \in \mathrm{R}$ be M and m , respectively. Then $\displaystyle \mathrm{M}^2-\mathrm{m}^2$ is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
1600
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.