Mathematics · 2024
JEE Main · 29 January 2024, Shift 1 · Q27
Equations of two diameters of a circle are 2 x-3 y=5 and 3 x-4 y=7. The line joining the points (-22/7,-4) and (-1/7, 3) intersects the circle at…
Equations of two diameters of a circle are $\displaystyle 2 x-3 y=5$ and $\displaystyle 3 x-4 y=7$. The line joining the points $\displaystyle \left(-\frac{22}{7},-4\right)$ and $\displaystyle \left(-\frac{1}{7}, 3\right)$ intersects the circle at only one point $\displaystyle \mathrm{P}(\alpha, \beta)$. Then, $\displaystyle 17 \beta-\alpha$ is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
2
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.