Let the circles C_1:(x-α)^2+(y-β)^2=r_1^2 and C_2:(x-8)^2+(y-15/2)^2=r_2^2 touch each other externally at the point (6,6). If the point (6,6) divides…

Let the circles $\displaystyle C_1:(x-\alpha)^2+(y-\beta)^2=r_1^2$ and $\displaystyle C_2:(x-8)^2+\left(y-\frac{15}{2}\right)^2=r_2^2$ touch each other externally at the point $\displaystyle (6,6)$. If the point $\displaystyle (6,6)$ divides the line segment joining the centres of the circles $\displaystyle C_1$ and $\displaystyle C_2$ internally in the ratio $\displaystyle 2: 1$, then $\displaystyle (\alpha+\beta)+4\left(r_1^2+r_2^2\right)$ equals