Mathematics · 2019
JEE Main · 9 April 2019, Shift 1 · Q72
Let S be the set of all values of x for which the tangent to the curve y=f(x)=x^3-x^2-2 x at ( x, y ) is parallel to the line segment joining the…
Let S be the set of all values of $\displaystyle x$ for which the tangent to the curve $\displaystyle y=f(x)=x^3-x^2-2 x$ at ( $\displaystyle x, y$ ) is parallel to the line segment joining the points $\displaystyle (1, f(1))$ and (-$\displaystyle 1$, f(-$\displaystyle 1$)), then S is equal to :
Official answer
(4)
$\displaystyle \left\{-\frac{1}{3}, 1\right\}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.