Let P be the point of intersection of the line (x+3)/3=(y+2)/1=(1-z)/2 and the plane x+y+z=2. If the distance of the point P from the plane 3 x-4…

Let P be the point of intersection of the line $\displaystyle \frac{x+3}{3}=\frac{y+2}{1}=\frac{1-z}{2}$ and the plane $\displaystyle x+y+z=2$. If the distance of the point P from the plane $\displaystyle 3 x-4 y+12 z=32$ is $\displaystyle q$, then $\displaystyle q$ and $\displaystyle 2 q$ are the roots of the equation