Let M be a 3 × 3 matrix such that M (1; 0; 0) = (1; 2; 3), M (0; 1; 0) = (0; 1; 2) and M (0; 0; 1) = (-1; 1; 1). If M (x; y; z) = (1; 7; 11), then…

Let M be a $\displaystyle 3 \times 3$ matrix such that $\displaystyle \mathrm{M}\left(\begin{array}{l}1 \\ 0 \\ 0\end{array}\right)=\left(\begin{array}{l}1 \\ 2 \\ 3\end{array}\right), \mathrm{M}\left(\begin{array}{l}0 \\ 1 \\ 0\end{array}\right)=\left(\begin{array}{l}0 \\ 1 \\ 2\end{array}\right)$ and $\displaystyle \mathrm{M}\left(\begin{array}{l}0 \\ 0 \\ 1\end{array}\right)=\left(\begin{array}{c}-1 \\ 1 \\ 1\end{array}\right)$. If $\displaystyle \mathrm{M}\left(\begin{array}{l}x \\ y \\ z\end{array}\right)=\left(\begin{array}{c}1 \\ 7 \\ 11\end{array}\right)$, then $\displaystyle x+y+z$ equals :