Let A = [1, 0, 0; 3, 1, 0; 9, 3, 1] and B =[ b_i j], 1 ≤ i, j ≤ 3. If B = A^99- I, then the value of (b_31- b_21)/(b_32) is:

Let $\displaystyle \mathrm{A}=\left[\begin{array}{lll}1 & 0 & 0 \\ 3 & 1 & 0 \\ 9 & 3 & 1\end{array}\right]$ and $\displaystyle \mathrm{B}=\left[\mathrm{b}_{i j}\right], 1 \leq i, j \leq 3$. If $\displaystyle \mathrm{B}=\mathrm{A}^{99}-\mathrm{I}$, then the value of $\displaystyle \frac{\mathrm{b}_{31}-\mathrm{b}_{21}}{\mathrm{~b}_{32}}$ is :