Mathematics · 2024
JEE Main · 8 April 2024, Shift 1 · Q10
Let I(x)=∫ 6/(sin^2 x(1- cot x)^2) d x. If I(0)=3, then I((π)/12) is equal to
Let $\displaystyle I(x)=\int \frac{6}{\sin ^2 x(1-\cot x)^2} d x$. If $\displaystyle I(0)=3$, then $\displaystyle I\left(\frac{\pi}{12}\right)$ is equal to
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 3 \sqrt{3}$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.