Let ∫ x^3 sin x d x= g (x)+ C, where C is the constant of integration. If 8(g((π)/2)+g^′((π)/2))=α π^3+β π^2+γ, α, β, γ ∈ Z, then α+β-γ equals:

Let $\displaystyle \int \mathrm{x}^3 \sin x \mathrm{~d} x=\mathrm{g}(x)+\mathrm{C}$, where C is the constant of integration. If $\displaystyle 8\left(g\left(\frac{\pi}{2}\right)+g^{\prime}\left(\frac{\pi}{2}\right)\right)=\alpha \pi^3+\beta \pi^2+\gamma, \alpha, \beta, \gamma \in Z$, then $\displaystyle \alpha+\beta-\gamma$ equals :