Mathematics · 2019
JEE Main · 12 January 2019, Shift 1 · Q69
Let S_k =(1+2+3+…+ k)/k. If S_1^2+ S_2^2+⋯+ S_10^2=5/12 A, then A is equal to:
Let $\displaystyle \mathrm{S}_{\mathrm{k}}=\frac{1+2+3+\ldots+\mathrm{k}}{\mathrm{k}}$. If
$\displaystyle \mathrm{S}_1{ }^2+\mathrm{S}_2{ }^2+\cdots+\mathrm{S}_{10}{ }^2=\frac{5}{12} \mathrm{~A}$, then A
is equal to :
Official answer
(4)
$\displaystyle 303$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.