Mathematics · 2019
JEE Main · 10 January 2019, Shift 1 · Q75
Let I =∫_- a^b (x^4-2 x^2) d x. If I is minimum then the ordered pair ( a, b ) is:
Let $\displaystyle \mathrm{I}=\int_{-\mathrm{a}}^{\mathrm{b}}\left(x^4-2 x^2\right) \mathrm{d} x$. If I is minimum then the ordered pair $\displaystyle (\mathrm{a}, \mathrm{b})$ is :
Official answer
(3)
$\displaystyle (-\sqrt{2}, \sqrt{2})$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.