Mathematics · 2021
JEE Main · 22 July 2021, Shift 2 · Q74
Let S_n denote the sum of first n -terms of an arithmetic progression. If S_10=530, S_5=140, then S_20- S_6 is equal to:
Let $\displaystyle \mathrm{S}_{\mathrm{n}}$ denote the sum of first n -terms of an arithmetic progression. If $\displaystyle \mathrm{S}_{10}=530, \mathrm{~S}_5=140$, then $\displaystyle \mathrm{S}_{20}-\mathrm{S}_6$ is equal to:
Official answer
(3)
$\displaystyle 1862$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.