Mathematics · 2023
JEE Main · 13 April 2023, Shift 2 · Q24
Let [α] denote the greatest integer ≤ α. Then [√ 1 ]+[√ 2 ]+[√ 3 ]+…+[√ 120 ] is equal to ____
Let $\displaystyle [\alpha]$ denote the greatest integer $\displaystyle \leq \alpha$. Then $\displaystyle [\sqrt{1}]+[\sqrt{2}]+[\sqrt{3}]+\ldots+[\sqrt{120}]$ is equal to $\displaystyle \_\_\_\_$
Official answer
From NTA’s final answer key for this paper.
825
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.