Mathematics · 2022
JEE Main · 28 June 2022, Shift 1 · Q7
Let [t] denote the greatest integer less than or equal to t. Then, the value of the integral ∫_0^1[-8 x^2+6 x-1] d x is equal to
Let $\displaystyle [t]$ denote the greatest integer less than or equal to $\displaystyle t$. Then, the value of the integral $\displaystyle \int_0^1\left[-8 x^2+6 x-1\right] d x$ is equal to
Official answer
(3)
$\displaystyle \frac{\sqrt{17}-13}{8}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.