Mathematics · 2026
JEE Main · 22 January 2026, Shift 2 · Q16
Let [·] denote the greatest integer function, and let f(x)= min {√ 2 x, x^2}. Let S ={x ∈(-2,2).: the function g (x)=|x|[x^2] is discontinuous at.x}.…
Let $\displaystyle [\cdot]$ denote the greatest integer function, and let $\displaystyle f(x)=\min \left\{\sqrt{2} x, x^2\right\}$.
Let $\displaystyle \mathrm{S}=\left\{x \in(-2,2)\right.$ : the function $\displaystyle \mathrm{g}(x)=|x|\left[x^2\right]$ is discontinuous at $\displaystyle \left.x\right\}$.
Then $\displaystyle \sum_{x \in \mathrm{~S}} f(x)$ equals
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 1-\sqrt{2}$
More from Continuity and Differentiability
- The number of points, at which the function f(x)= max {6 x, 2+3 x^2}+|x-1| cos |x^2-1/4|, x ∈(-π, π), is not differentiable, is ____.2026
- The number of points in the interval [2,4], at which the function f(x)=[x^2-x-1/2], where [•] denotes the greatest integer function, is…2026
- Let f(x)= {x^3+8; x<0, x^2-4; x ≥ 0,} and g(x)= {(x-8)^1 / 3; x<0, (x+4)^1 / 2; x ≥ 0.} Then the number of points, where the function gof is…2026
- For the function f(x)=e^sin |x|-|x|, x ∈ R, consider the following statements: Statement I: f is differentiable for all x ∈ R. Statement II: f is…2026
- Let f(x)= {e^x-1, x<0; x^2-5 x+6, x ≥ 0} and g(x)=f(|x|)+|f(x)|. If the number of points where g is not continuous and is not differentiable are α…2026
JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.