Let f(x)= {x^3+8; x<0, x^2-4; x ≥ 0,} and g(x)= {(x-8)^1 / 3; x<0, (x+4)^1 / 2; x ≥ 0.} Then the number of points, where the function gof is…

Let $\displaystyle f(x)=\left\{\begin{array}{ll}x^3+8 ; & x<0, \\ x^2-4 ; & x \geq 0,\end{array}\right.$ and $\displaystyle g(x)= \begin{cases}(x-8)^{1 / 3} ; & x<0, \\ (x+4)^{1 / 2} ; & x \geq 0 .\end{cases}$ Then the number of points, where the function gof is discontinuous, is $\displaystyle \_\_\_\_$.