Mathematics · 2025
JEE Main · 29 January 2025, Shift 2 · Q5
Let α, β(α ≠ β) be the values of m, for which the equations x+y+z=1; x+2 y+4 z= m and x+4 y+10 z= m^2 have infinitely many solutions. Then the value…
Let $\displaystyle \alpha, \beta(\alpha \neq \beta)$ be the values of m , for which the equations $\displaystyle x+y+z=1 ; x+2 y+4 z=\mathrm{m}$ and $\displaystyle x+4 y+10 z=\mathrm{m}^2$ have infinitely many solutions. Then the value of $\displaystyle \sum_{\mathrm{n}=1}^{10}\left(\mathrm{n}^\alpha+\mathrm{n}^\beta\right)$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 440$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.