Mathematics · 2025
JEE Main · 8 April 2025, Shift 2 · Q4
Let A = [2, 2+p, 2+p+q; 4, 6+2 p, 8+3 p+2 q; 6, 12+3 p, 20+6 p+3 q]. If det ( adj ( adj (3 A)))=2^m · 3^n, m, n ∈ N, then m+n is equal to
Let $\displaystyle \mathrm{A}=\left[\begin{array}{ccc}2 & 2+p & 2+p+q \\ 4 & 6+2 p & 8+3 p+2 q \\ 6 & 12+3 p & 20+6 p+3 q\end{array}\right]$. If $\displaystyle \operatorname{det}(\operatorname{adj}(\operatorname{adj}(3 A)))=2^m \cdot 3^n, m, n \in \mathrm{~N}$, then $\displaystyle m+n$ is equal to
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 24$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.