Mathematics · 2023
JEE Main · 8 April 2023, Shift 2 · Q8
Let a_n be the n^th term of the series 5+8+14+23+35+50+… and S_n =Σ_k=1^n a_k. Then S_30-a_40 is equal to
Let $\displaystyle \mathrm{a}_{\mathrm{n}}$ be the $\displaystyle \mathrm{n}^{\text {th }}$ term of the series $\displaystyle 5+8+14+23+35+50+\ldots$ and $\displaystyle \mathrm{S}_{\mathrm{n}}=\sum_{k=1}^n a_k$. Then $\displaystyle \mathrm{S}_{30}-a_{40}$ is equal to
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 11290$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.