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Mathematics · 2023

JEE Main · 24 January 2023, Shift 2 · Q73

Let y=y(x) be the solution of the differential equation (x^2-3 y^2) d x+3 x y d y=0, y(1)=1. Then 6 y^2( e ) is equal to

Let $\displaystyle y=y(x)$ be the solution of the differential equation $\displaystyle \left(x^2-3 y^2\right) d x+3 x y d y=0, y(1)=1$. Then $\displaystyle 6 y^2(\mathrm{e})$ is equal to
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.