Let y=y(x) be the solution curve of the differential equation (d y)/(d x)=y/x(1+x y^2(1+ log_e x)), x>0, y(1)=3. Then (y^2(x))/9 is equal to:

Let $\displaystyle y=y(x)$ be the solution curve of the differential equation $\displaystyle \frac{d y}{d x}=\frac{y}{x}\left(1+x y^2\left(1+\log _e x\right)\right), x>0, y(1)=3$. Then $\displaystyle \frac{y^2(x)}{9}$ is equal to :