Mathematics · 2025
JEE Main · 24 January 2025, Shift 1 · Q20
Let y=y(x) be the solution of the differential equation (x y-5 x^2 √(1+x^2)) d x+(1+x^2) d y=0, y(0)=0. Then y(√ 3 ) is equal to
Let $\displaystyle y=y(x)$ be the solution of the differential equation $\displaystyle \left(x y-5 x^2 \sqrt{1+x^2}\right) d x+\left(1+x^2\right) d y=0, y(0)=0$. Then $\displaystyle y(\sqrt{3})$ is equal to
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle \frac{5 \sqrt{3}}{2}$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.