Mathematics · 2025
JEE Main · 3 April 2025, Shift 2 · Q20
Let y=y(x) be the solution of the differential equation (d y)/(d x)+3( tan^2 x) y+3 y= sec^2 x, y(0)=1/3+e^3. Then y((π)/4) is equal to
Let $\displaystyle y=y(x)$ be the solution of the differential equation $\displaystyle \frac{d y}{d x}+3\left(\tan ^2 x\right) y+3 y=\sec ^2 x, y(0)=\frac{1}{3}+e^3$. Then $\displaystyle y\left(\frac{\pi}{4}\right)$ is equal to
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \frac{4}{3}$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.