Mathematics · 2026
JEE Main · 23 January 2026, Shift 1 · Q20
Let y=y(x) be the solution of the differential equation x^4 d y+(4 x^3 y+2 sin x) d x=0, x>0, y((π)/2)=0. Then π^4 y((π)/3) is equal to:
Let $\displaystyle y=y(x)$ be the solution of the differential equation $\displaystyle x^4 \mathrm{~d} y+\left(4 x^3 y+2 \sin x\right) \mathrm{d} x=0, x>0, y\left(\frac{\pi}{2}\right)=0$. Then $\displaystyle \pi^4 y\left(\frac{\pi}{3}\right)$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 81$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.